Question

The distance between two points (3,-9) and (-2,3)

Answer 1

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we use the distance formula,

$d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}$

give, the points are (3,-9) and (-2,3)

so substituting the values in formula,

$d = \sqrt{(-2 - 3)^2 + (3--9)^2}$

$d = \sqrt{(-5)^2+12^2}$

$d = \sqrt{25+144}$

$d = \sqrt{169}$

$d = 13$ units

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