Question

the distance between two points (7,10) and (-2,5) is ----units8​

Answer 1

Answer:

Required distance is √106 units.

Step-by-step explanation:

We know that,

$Distance\:between\:two\:points\:=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}\:units\:\\Now,\:taking\:x_{1}=7,\:x_{2}=-2\:and\:y_{1}=10,\:y_{2}=5\\By\:putting\:the\:above\:values,\:we\:get,\\Distance=\sqrt{(7-(-2))^{2}+(10-5)^{2}}\\=\sqrt{(7+2)^{2}+(5)^{2}}\\=\sqrt{(9)^{2}+25}\\=\sqrt{81+25}\\=\sqrt{106}$

So, required distance is √106 units.

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