Question

the distance between two points p and q is 13 units. if the ordered pair of p is (2,12) and q lies in the x axis, what is the ordered pair of q?

Answer 1

distance between 2 points=√(x2-x1)^2 + (y2-y1)^2

p=(2,12) q=(x,0)

√[(x-2)^2 + (0-12)^2] = 13

(x-2)^2 + (-12)^2 = (13)^2

(x-2)^2 + 144 = 169

(x-2)^2 = 169 - 144

(x-2)^2 = 25

(x-2) = √25

x-2 = 5

x= 5+2

x=7....
q=(7,0)

hope this would be helpful

Answer 2

Answer:

Step-by-step explanation:

Hope it helps