Question

The distance between two slits in young experiment is 0.1mm and the distance of the screen from slits is 100cm if the wavelength of light is 5000A⁰ the width of the fringe is_

Answer 1

Answer:

$\boxed{\sf Fridge \ width \ (\beta) = 5 \ mm}$

Given:

Distance between two slits (d) = 0.1 mm = $\sf 10^{-4} \ m}$

Distance of the screen from slits (d) = 100 cm = 1 m

Wavelength of light ($\sf \lambda$) = 5000 $\sf \text{\AA}$ = $\sf 5 \times 10^{-7}$

To Find:

Width of the fridge ($\sf \beta$)

Explanation:

Formula:

$\boxed{ \bold{\sf \beta = \frac{\lambda D}{d}}}$

Substituting values of $\sf \lambda$, D & d in the equation:

$\sf \implies \beta = \frac{5 \times {10}^{ - 7} \times 1 }{ {10}^{ - 4} }$

$\sf \implies \beta = 5 \times {10}^{ - 7 - ( - 4)}$

$\sf \implies \beta = 5 \times {10}^{ - 7 + 4}$

$\sf \implies \beta = 5 \times {10}^{ - 3} \: m$

$\sf \implies \beta = 5 \: mm$

$\therefore$

Width of the fridge ($\sf \beta$) = 5 mm