The distance between two station A and B is 500 km . Two trains start from stations,at the same time on parallel tracks to cross each other . The speed of one train is 20 km/h less than that of the other .After three and quarter hours, the train are 45 km apart .find the speed of each train.
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Answer:
80 km/hr
100 km/hr
Step-by-step explanation:
Let speed of train A be x km/hr
therefore speed of train B = (x+20) km/hr
AB= 500 km/hr
distance between the trains = 45 km/hr
after 3 hrs 15 minutes= 13/4 hrs
two trains are moving opposite to each other hence,
Time interval = quarter hour (0.25 hour)
= 15 minute
both trains travel towards each other,
( their direction is opposite )
Relative speed = X + X + 20 = 2x + 20
Then apply formula,
speed = displacement / time interval
Time interval = displacement / speed
time = Distance between two trains / their speed
0.25 hour = 45/(2x + 20 )
45/(2x+20) = 0.25
45 = 0.5X + 5
0.5X = 45 - 5
0.5X = 40
X = 40/0.5
X = 80 km /h
speed of slower Train = X = 80 km / h
speed of faster Train = X + 20
= 80 + 20
= 100 km / h
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