The distance between two station is 425 km. Two train start simultaneously from these stations on a parallel tracks to cross each other. The speed of one trains is greater than the other is 5 km/ hr. If the distance between two train after 3 hours of their start is 20 km, find the speed of each train
Answers
Answered by
61
Given that distance between two stations= 425 km
Let the speed of the first train be x km/hr
Then the speed of other train is (x+5) km/hr
Distance travelled by first train in 3 hours = 3 × x km/hr = 3x km
Distance travelled by second train in 3 hours = 3× (x+5) km/hr = 3x +15 km
Also given that distance between the trains after three hours= 20
By given data
3x + 20 + 3x+15 = 425
6x + 35 = 425
6x = 425 - 35 = 390
x = 390 / 6 = 65 km/hr
Therefore speed of first train = x = 65 km/hr
speed of second train = x + 5 = 65 + 5 = 70 km/hr
please mark as brilliancy..
Let the speed of the first train be x km/hr
Then the speed of other train is (x+5) km/hr
Distance travelled by first train in 3 hours = 3 × x km/hr = 3x km
Distance travelled by second train in 3 hours = 3× (x+5) km/hr = 3x +15 km
Also given that distance between the trains after three hours= 20
By given data
3x + 20 + 3x+15 = 425
6x + 35 = 425
6x = 425 - 35 = 390
x = 390 / 6 = 65 km/hr
Therefore speed of first train = x = 65 km/hr
speed of second train = x + 5 = 65 + 5 = 70 km/hr
please mark as brilliancy..
nishu7861:
thanks
Answered by
26
Answer: 65km/hr & 70km/hr
Step-by-step explanation:
Let speed of one train be x km/hr.
Then, speed of other train
= x+5 km/hr.
Distance travelled by 1st train in 3hrs = 3x km.
Distance travelled by 2nd train in 3hrs = 3(x+5)km = 3x+15km.
3x + 3x+15 + 20 = 425
6x+35 = 425
6x = 425-35
6x = 390
x = 65
Hence, speed of 1st train = 65km/hr
Speed of 2nd train = 65+5 = 70km/hr.
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