Question

The distance between two stations A and B is 200 km.Two trains start at the same time from A and B in the opposite directions towards each other. After 2 hours, the distance between them is 50 km. If the speed of one train is 5km/h more than the other train, find their speeds.

Answer 1

Let X be the speed of the slower train in km/hr
speed of other one will be (x+5) km/hr.
Now,
distance travelled by slower train in 2 hrs= speed × time
= x×2
= 2x
distance travelled by Faster train in 2 hrs= 2*(x+5).
Now ,
2x+ 2(x+5) +50=200
→x= 35km/hr see picture
speed of second train = 30+5 = 35km/hr

Answer 2

Solutions :-

️Let the speed of the train Travel slower ( x Km / h)

A.T.Q speed of Faster train will be ( x + 5 Km / h)

Distance traveled by slower train in 2 hours

=> speed = distance / time

=> Distance = speed × time

=> Distance = ( x ) × 2

=> Distance = 2 x Km

Distance traveled by faster train

=> Distance = speed × time

=> Distance = ( x + 5 ) × 2

=>Distance = ( 2 x + 10 ) Km


️ Now total distance was 200 and they had traveled 150 Km after 2 hours , So

=> 2 x + 2 x + 10 = 150

=> 4 x + 10 = 150

=> 4 x = 140

=> x = 35 Km / h


️ Now speed of slower train is 35Km / h

Speed of Faster train is ( 35 + 5 ) = 40 Km / h

THANKS