The distance between two stations A and B is 200 km. Two trains start at the same time from A and B in the opposite directions towards each other. After 2 hours, the distance between them is 50 km. if the speed of one train is 5 km/h more than the other train, find their speed.
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the speed of another train is 65 kmph
Ayanhusain:
Please give me full solution
your answer is wrong
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Solutions :-
️Let the speed of the train Travel slower ( x Km / h)
A.T.Q speed of Faster train will be ( x + 5 Km / h)
Distance traveled by slower train in 2 hours
=> speed = distance / time
=> Distance = speed × time
=> Distance = ( x ) × 2
=> Distance = 2 x Km
Distance traveled by faster train
=> Distance = speed × time
=> Distance = ( x + 5 ) × 2
=>Distance = ( 2 x + 10 ) Km
️ Now total distance was 200 and they had traveled 150 Km after 2 hours , So
=> 2 x + 2 x + 10 = 150
=> 4 x + 10 = 150
=> 4 x = 140
=> x = 35 Km / h
️ Now speed of slower train is 35Km / h
Speed of Faster train is ( 35 + 5 ) = 40 Km / h
THANKS
️Let the speed of the train Travel slower ( x Km / h)
A.T.Q speed of Faster train will be ( x + 5 Km / h)
Distance traveled by slower train in 2 hours
=> speed = distance / time
=> Distance = speed × time
=> Distance = ( x ) × 2
=> Distance = 2 x Km
Distance traveled by faster train
=> Distance = speed × time
=> Distance = ( x + 5 ) × 2
=>Distance = ( 2 x + 10 ) Km
️ Now total distance was 200 and they had traveled 150 Km after 2 hours , So
=> 2 x + 2 x + 10 = 150
=> 4 x + 10 = 150
=> 4 x = 140
=> x = 35 Km / h
️ Now speed of slower train is 35Km / h
Speed of Faster train is ( 35 + 5 ) = 40 Km / h
THANKS
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