Question

The distance between two stations a and b is 230km. Two cars start simultaneously from a and b in the opposite direction and the distance between them after 3hours is 20km. If the speed of one car is less t
han that of the other by 10km/hr. Find the speed of first car?

Answer 1

Answer:

40km/hr

Step-by-step explanation:

Let the speed of the first car be x

Therefore, the speed of the second car will be x-10

Distance between both the cars after 3 hours = 20km

Therefore, sum of distance travelled by both the cars in 3 hours = 230km - 20km = 210km

Distance/Time = Speed

$210 \div 3 = x + (x - 10) \\ 70 = 2x - 10 \\ 2x = 80 \\ x = 40$

Therefore, the speed of the first car will be 40 km/hr

Hope this helps!!