Math, asked by devkikhillan, 6 months ago

The distance between two stations A and B is
250 km. Two trains start simultaneously from
A and B in opposite directions. The distance
1
between them after 2 hours is 25 km. If the
2
speed of one train is 10 km/hr. more than the
other. Find the speed of each of the trains.​

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Answers

Answered by kartik0303
11

Answer:

50km/hr

Step-by-step explanation:

The distance between the stations is 250km and after 2.5 hours the trains are 25km apart.

The total distance that the trains have traveled is 250km - 25km or 225km.

Let X be the speed of the slower train in km/hr

225km=2.5X+2.5{X+10}

Simplify the equation

225=2.5X+2.5X+25

Combine like terms

225=5X+25

Subtract 25 from both sides

200=5X

Divide both sides by 5

40=X

The slower train is moving at 40km/hr.

That means that the faster train is moving at 50km/hr

hope it help.

Answered by arshpreetsingh94834
2

Step-by-step explanation:

Let in the speed of the slower teain

The dotal distance that the train has have travelled. e 250 km-25km 2225 km

225km = 25n + 2.5(a + 10)

225 = 25 * 2z + 2 * 5x + 25

225 = 5x + 25 Subtract 25 from both sides. 2002521 n = 300/2 * 40

401km/h

The slower train is moring at 40 km/h

That means that the faster trin is moning at 50km/h

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