The distance between two stations A and B is
250 km. Two trains start simultaneously from
A and B in opposite directions. The distance
1
between them after 2 hours is 25 km. If the
2
speed of one train is 10 km/hr. more than the
other. Find the speed of each of the trains.
![](https://hi-static.z-dn.net/files/d8a/2ef8ea31d3f5ca5c9b9d563ee5c0eb33.jpg)
Answers
Answer:
50km/hr
Step-by-step explanation:
The distance between the stations is 250km and after 2.5 hours the trains are 25km apart.
The total distance that the trains have traveled is 250km - 25km or 225km.
Let X be the speed of the slower train in km/hr
225km=2.5X+2.5{X+10}
Simplify the equation
225=2.5X+2.5X+25
Combine like terms
225=5X+25
Subtract 25 from both sides
200=5X
Divide both sides by 5
40=X
The slower train is moving at 40km/hr.
That means that the faster train is moving at 50km/hr
hope it help.
Step-by-step explanation:
Let in the speed of the slower teain
The dotal distance that the train has have travelled. e 250 km-25km 2225 km
225km = 25n + 2.5(a + 10)
225 = 25 * 2z + 2 * 5x + 25
225 = 5x + 25 Subtract 25 from both sides. 2002521 n = 300/2 * 40
401km/h
The slower train is moring at 40 km/h
That means that the faster trin is moning at 50km/h