The distance between two stations 'A' and 'B' is 300 km. A train starts from station
‘A’ with a speed of 30 km./hr. At the same time another train starts from station 'B'
in the opposite direction with a speed of 45 km./hr. At what distance from station
'A' will they meet?
(A) 100 km (B) 120 km. (C) 180 km. (D) 200 km
Answers
ANSWER
Let the trains start from station A and station B respectively.
Let the first train start from station A and the second train start from station B at the same time and move towards each other.
Let the speed of the first train be x km/hr
∴ the speed of the second train =(x+20) km/hr
Distance travelled by first train in 2 hours =2x km
Distance travelled by second train in 2 hours =2(x+20) km =(2x+40) km
Given, distance between two stations =300 km
According to the given condition, we have
Distance travelled by first train + Distance travelled by second train +20=300
i.e., 2x+(2x+40)+20=300
4x+60=300
4x=300−60 ....[Transposing 60 to RHS]
4x=240
Thus, x=
4
240
=60
∴ Speed of the first train =60 km/hr and
speed of the second train =(60+20) krn/h =80 km/hr.
Answer:
B) 120 km
Step-by-step explanation:
Speed of the first train= 30km/hr
Speed of the second train=45km/hr
Time both trains will meet at = 300/30+45
=300/75= 4
So both trains will meet after 4 hours
Distance from station A = 4×30 = 120 km