Question

The distance between two stations A and B is 310 km. Two motorcyclists start simultaneously from A and B in the
opposite directions and the distance between them after 4 hours is 30 km. If the speed of one motorcyclist is less
than that of the other by 10 km/h, find the speed of each motorcyclist
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Answer 1

Step-by-step explanation:

Total distance b/w them=310Km

Time=4hour

Relative speed= Sum of speed of both motors.

= (310-30)/4 km/hr(coz remaining distance was covered by them in same time so the sum of their speed with common denominator time would be this.)

=280/4=70km/hr

Let the speed of one motor be x km/hr then other equals (x-10)km/hr

Henceforth the equation is

x + x-10 = 70

=>2x-10=70

=>x-5 =35

=>x=40

so the speed of each motor is 40 km per hr and 40 minus 10, I.e., 30km per hr.