Question

the distance between two stations A and B is 540 km. two trains start simultaneously from these stations on parallel tracks to cross each other. the speed of one of them is greater than the other by 5 km/ hr. if the distance between these two trains after 3 hours of their start is 165 km, find the speed of each

Answer 1

Let speed of slower train = X kmph
Speed of faster train = (X + 5) kmph

Distance between the trains = 165 km
Time = 3 hrs
Since both trains travel towards each other (opposite directions),
Relative speed = X + X+5 = 2X + 5

D/S = T
165/(2X + 5) = 3
165 = 6X + 15
6X = 150
X=25 kmph

Speed of slower train = 25 kmph
Speed of faster train = 30 kmph
Hope this helps

Answer 2

Answer:

Step-by-step explanation:

Let the speed of train A be x km/hr

And the speed of train B be x+5 km/hr

Time = 3 hr

Distance = Speed * Time

Therefore A's Distance = 3*x, ie 3x

And B's Distance= 3*(x+5), ie 3x +15

Therefore,

3x+3x+15+165=540

( because the total distance between both station is 540 and the distance between both train is 165)

6x+15=375

6x=360

X= 60

Speed of Train A = 60 km/hr

Speed of Train B = 60+5 ie 65 km/hr