The distance between two stations c and d is 230 km. Two motorists start simultaneously from c and d in the opposite directions and the distance between them after 3hours is 20 km. If the speed of one motorist is less than that of the other by 10 km /hr. Find the speed of each motorist
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Let A and B two motorcyclists are seperated 230km apart.
Let speed of motorcyclist A is x km/h then speed of motorcyclist B is (x - 10) km/h
a/c to question,
both are moving in opposite directions. and after 3 hours, seperation between them = 20km.
so, distance travelled by A in 3 hours = 3x km
distance travelled by B in 3 hours = 3(x - 10)km
now, distance travelled by A + distance travelled by B + 20km = 230km
or, 3x + 3(x - 10) = 210
or, 6x = 240
or, x = 40
hence, speed of motorcyclist A = 40km/h
speed of motorcyclist A = 40km/hand speed of motorcyclist B = (40 - 10) = 30km/h
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