Question

The distance between two stations is 230 km. Two scooterists start simultaneously towards each other one from
other from B. If the speed of one scooterist is 10 km less than that of the other, then find the speed of eachs
Two persons sta
km/hour and meets the second person coming from opposite direction anter
if the distance between them after 3 hours of their start is 20 km.​

Answer 1

Answer:

Let speed of bike A is X.

Than speed of bike B will be X+10.

Total distance traveled by both bikes is 210

Bicoz difference is only 20km.

(X+10)3+3X=210.

BY equating it

X=30.

That's why speed of A=30

B=40.

Step-by-step explanation:

Answer 2

According to the question after time 2h

300=(v+7)2+34+v2 [dist= velocity× time]

300=2v+14+34+2v

300=4v+48

4v=252

v=63 km/h

Check: Put v=63 in the equation then RHS converts to

(63+7)2+34+63×2

70×2+34+63×2

140+34+126

300

Which is equal to LHS.