The distance between two stations is 300 km. Two motorcyclists start simultaneously from these stations and move towards each other. The speed of one of them is 7 km/hr more than the other. If the distance between them after two hours of their start is 34 km, find the speed of each motorcyclist.
Answers
Step-by-step explanation:
According to the question after time 2h
300=(v+7)2+34+v2 [dist= velocity× time]
300=2v+14+34+2v
300=4v+48
4v=252
v=63 km/h
Check: Put v=63 in the equation then RHS converts to
(63+7)2+34+63×2
70×2+34+63×2
140+34+126
300
Which is equal to LHS.
Answer :D
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EXPLANATION-:
According to the question
After time 2h
300 =(v+ 7) 2 + 34 + v2
[distance = velocity× time]
300 = 2v +14 +34 + 2v
300 = 4v + 48
4v = 252
v = 63 km/h
Check: Put v = 63 in the equation then
RHS converts to
(63 + 7)2 +34+63 x 2
140+ 34+ 126
= 300
Which is equal to L.H.S
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So speed of first motorcyclist is
63km/ph
Second motorcyclist speed is
(63km/ph + 7 ) = 70 km/ph
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First motorcyclist speed = 63km/ph
Second motorcyclist speed = 70 km/ph
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