The distance between two stations is300km. Two motor cyclists start simulstaneouly from these stations and move towards each other. The only speed of one is 7 km /hr faster than that of the other. If the rate distance between them after 2 hours of their start is 34 km, find the speed of each motor-cyclists .
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Let the speed of 1st. Mouercyclist be x
Then, 2nd speed =x+7
A/q,
2* x +2(x+7)+34 =300
2x +2x +14+34=300
4x +48=300
4x =252
X=63
1st. Speed = 69km/h
2nd. Speed =(x+7)=(69+7) km/h=76 km/h
Then, 2nd speed =x+7
A/q,
2* x +2(x+7)+34 =300
2x +2x +14+34=300
4x +48=300
4x =252
X=63
1st. Speed = 69km/h
2nd. Speed =(x+7)=(69+7) km/h=76 km/h
Ankita1234:
First speed 63km/hr...and the Two second speed is 70 km/hr
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