The distance between two successive orbits of H-atom is
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Explanation:
The ionization energy of H-atom in the first excited state is negative of one fourth of the energy of an electron in the ground state C Sol.
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Distance between the 2nd and the 3rd orbits = distance of 3rd orbit – diistnace of second orbit from the nucleus.d3 = 0.529 x n2/z x 10-10 m = 0.529 x 9 x 10-10 md2 = 0.529 x 4 x 10-10 md3 – d2 = 0.529 x 5 x 10-10 m= 2.645 x 10-10 m is the distance between the 2nd the 3rd orbits.
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