the distance between two towns is 300 km two cars start simultaneously from these towns and move towards each other the speed of one car is more than the other by 7km per hour if the distance between the cars after 2 hours in 34km find the speed of thecar
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Answered by
561
let the speed of the first car be x
then speed of other car is (x+7)
distance covered by fist car after 2 hour = 2x
distance covered by 2nd car = 2(x+7) = 2x+14
now , 2x+2x+14+34 = 300
4x+14+34 = 300
4x+48 = 300
4x = 300 - 48
x = 252 / 4 = 63 km/hr
distance of 2nd car = 63 + 7 = 70km/hr
then speed of other car is (x+7)
distance covered by fist car after 2 hour = 2x
distance covered by 2nd car = 2(x+7) = 2x+14
now , 2x+2x+14+34 = 300
4x+14+34 = 300
4x+48 = 300
4x = 300 - 48
x = 252 / 4 = 63 km/hr
distance of 2nd car = 63 + 7 = 70km/hr
Answered by
256
Answer:
Let the speed of car 1 = x km/h
So the speed of car 2 = x+7 km/h
Distance covered by car 1 in 2 hours =2x
Distance covered by car 2 in 2 hours =2(x+7) =2x+14
ATQ
2x + 2x +14 + 34 =300
4x + 48 =300
4x =300-48
4x =252
x = 252/4
x = 63
So the speed of Car 1 = x = 63km/h
The speed of car 2 = x+7 = 63+7 =70km/h
Step-by-step explanation:
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