Question

the distance between two towns is 3OO km. two cars start simultaneously from these towns and move towards each other. the speed of one car is more than the other by 7km/hr .if the distance between the cars after 2 hours is 34km/hr find the speed of the cars ​

Answer 1

Let speed of first car be "x" km/hr.

The speed of one car is more than the other by 7km/hr.

Speed of another car = (x + 7) km/hr.

First car covered a distance in 2 hrs.

So, Distance covered by first car = (2x) km

Distance covered by another car = 2(x + 7) km

Also, given that distance between two towns is 300.

And the distance between the cars after 2 hours is 34km/hr

According to question,

=> 2x + 2(x + 7) + 34 = 300

=> 2x + 2x + 14 + 34 = 300

=> 4x + 48 = 300

=> 4x = 300 - 48

=> 4x = 252

=> x = 63 km/hr.

So,

Distance of first car = 63 km/hr.

Distance of another car = x + 7

=> 63 + 7

=> 70 km/hr.

Answer 2

Answer:

Step-by-step explanation:

Given :-

The distance between two towns is 300 km.

Two cars start simultaneously from these towns and move towards each other.

The speed of one car is more than the other by 7km/hr.

If the distance between the cars after 2 hours is 34km/h.

To Find :-

Speed of cars.

Solution :-

Let the speed of 1st car  = x km/h

Then the speed of 2nd car = x + 7 km/h

Distance covered by 1st car in 2 hours = 2x

Distance covered by 2nd car in 2 hours = 2(x + 7) = 2x + 14

According to the question

⇒ 2x + 2x +14 + 34 =300

⇒  4x + 48 =300

⇒  4x =300-48

⇒  4x =252

⇒  x = 252/4

⇒ x = 63

Speed of 1st car = 63 km/h

Speed of 2nd car = x + 7 = 63 + 7 = 70 km/h

Hence, Speed of 1st car and 2nd car is 63 km/h and 70 km/h.