Question

the distance between two towns on a national highway is 600km .A and B start simultaneously from these cities on their bikes towards each other. they meet after 4 hours and if the speed of B is 10kmph more than of A .find their speed ​

Answer 1

Given data :-

• The distance between two towns on a national highway is 600km.
• A and B start simultaneously from these cities on their bikes towards each other.
• A and B meet after 4 hours and if the speed of B is 10kmph more than of A.

Solution :-

Let, speed of A be ' x '

→ Speed of A = x

Hence, according to given

→ Speed of B = x + 10 .....( 1 )

→ Total time taken by A and B = 4 hour

→ Total distance travel by A and B = 600km

Now, we use formula of relative speed

→ Relative speed of A and B

= {Total speed}/{Total time}

→ x + x + 10 = 600/4

→ 2x + 10 = 150

→ 2x = 150 - 10

→ 2x = 140

→ x = 140/2

→ x = 70 km/hr

Hence, speed of A is 70 km/hr.

Put value of x in eq. ( 1 )

→ Speed of B = x + 10

→ Speed of B = 70 + 10

→ Speed of B = 80 km/hr

Hence, speed of B is 80 km/hr.

Hence, speed of A and B is 70 km/hr and 80 km/hr respectively.