Question

The distance between two towns on a national highway is 600 km. A and B start
simultaneously from these cities on their bikes towards each other. They meet after
4 hours and if the speed of B is 10 kmph more than that of A, find their speeds.​

Answer 1

Answer:

Let n be the speed of bike A. Then the speed of B is n+10. So:

4n+4(n+10)=600

8n= 560

n=70 km/h

n+10=80 km/h

HOPE IT HELPS!!!!

Answer 2

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★Answer★

Let the speed of A = x kmph

Then, The speed Of B = x+10 kmph

Time Travelled = 4 hour.

∴ Distance Travelled By A

= Speed × Time

= 4x km

Distance Traveled by B

= Speed × Time = 4(x+10)

= (4x+40)km

According To Question,

➠ 4x +4x +40 = 600

➠ 8x =560

➠x = 70 kmph

Therefore,

The speed of A = 70kmph and speed of B = 80kmph.