Math, asked by ushkamrameshkumar, 16 days ago

the distance between two trains is 200km A is coming at 40km/h and B is running at 60/h they are running towards each other at wt time they will meet​

Answers

Answered by huzaifa445366
1

Answer:

Calculations:

Calculations:Let speeds of both the trains be x km/h and (x + 8) km/h, respectively.

Calculations:Let speeds of both the trains be x km/h and (x + 8) km/h, respectively.Then, according to the question,

Calculations:Let speeds of both the trains be x km/h and (x + 8) km/h, respectively.Then, according to the question,∴ 200 = x × 5 + (x + 8) × 5

Calculations:Let speeds of both the trains be x km/h and (x + 8) km/h, respectively.Then, according to the question,∴ 200 = x × 5 + (x + 8) × 5⇒ 200 = 5x + 5x + 40

Calculations:Let speeds of both the trains be x km/h and (x + 8) km/h, respectively.Then, according to the question,∴ 200 = x × 5 + (x + 8) × 5⇒ 200 = 5x + 5x + 40⇒ 200 = 10x + 40

Calculations:Let speeds of both the trains be x km/h and (x + 8) km/h, respectively.Then, according to the question,∴ 200 = x × 5 + (x + 8) × 5⇒ 200 = 5x + 5x + 40⇒ 200 = 10x + 40⇒ 160 = 10x

Calculations:Let speeds of both the trains be x km/h and (x + 8) km/h, respectively.Then, according to the question,∴ 200 = x × 5 + (x + 8) × 5⇒ 200 = 5x + 5x + 40⇒ 200 = 10x + 40⇒ 160 = 10x⇒ x = 16 km/h

Calculations:Let speeds of both the trains be x km/h and (x + 8) km/h, respectively.Then, according to the question,∴ 200 = x × 5 + (x + 8) × 5⇒ 200 = 5x + 5x + 40⇒ 200 = 10x + 40⇒ 160 = 10x⇒ x = 16 km/h∴ (x + 8) = 24 km/h

Calculations:Let speeds of both the trains be x km/h and (x + 8) km/h, respectively.Then, according to the question,∴ 200 = x × 5 + (x + 8) × 5⇒ 200 = 5x + 5x + 40⇒ 200 = 10x + 40⇒ 160 = 10x⇒ x = 16 km/h∴ (x + 8) = 24 km/hHence, speeds of both the trains are 16 km/h and 24 km/h.

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