the distance between x, 3 and 4, 5 is root 5 then find x
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formula=√(x2-x1)^2+(y2-y1)^2
2√5=√(4-x)^2+(5-3)^2
(2√5)^2=(4-x)^2+4
20=16+x^2-8x+4
20-20=x^2-8x
x^2=8x
x=8
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√(x2-x1)^2+(y2-y1)^2
2√5=√(4-x)^2+(5-3)^2
(2√5)^2=(4-x)^2+4
20=16+x^2-8x+4
20-20=x^2-8x
x^2=8x
x=8
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