The distance between (x,7)and (1,3) is 5 units find x
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by distance formula
√(3-7)^2 + (1-x)^2 = 5
squaring on both side
16 + (x-1)^2 =25
x ^2 -2x +1 = 9
x^2 -2x -8 =0
factor s are x = 4 and -2
√(3-7)^2 + (1-x)^2 = 5
squaring on both side
16 + (x-1)^2 =25
x ^2 -2x +1 = 9
x^2 -2x -8 =0
factor s are x = 4 and -2
sowmiya35:
kalash see my q
help me with my sum
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