the distance btween the point (3,1)and(0,x)is 5units find x
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Answer:
x= 5 & (-3)
Step-by-step explanation:
5=√(3-0)² +(1-x)²
5=√3²+(x²+1-2x)
5=√9+x²+1-2x
5=√10+x²-2x
on squaring both side,we get
25=x²-2x+10
15=x²-2x
x²-2x-15=0
x²-5x+3x-15=0
x(x-5)+3(x-5)=0
(x-5)(X+3)=0
therefore x=5 & (-3)
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