Question

The distance covered by a car at a time, t is given by x = 20t + 6t4,calculate
(i) the instantaneous velocity when t = 1
(ii) the instantaneous acceleration when t = 1

Answer 1

So , we have

     x = 20t + 6t^4

velocity = d/dx (Position)

           v  = 20 + 24t^3

Acceleration = d/dx (velocity)

             a = 72t^2

(i) the instantaneous velocity when t = 1

Ans :-   v = 20 + 24 (1)^3

           v = 20+24

             v= 44 m/s

(ii) the instantaneous acceleration when t = 1

Ans :- a = 72t^2

          a = 72 (1)^2

          a = 72*1

          a = 72 m/s^2

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