The distance covered by a particle varies with time as X = at^2- bt^3 . find the time at which its acceleration is zero
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is it a/3b ? because,
all u have to do is differentiate the expression 2 times w.r.t time t, because as we know, dx/dt=v and dv/dt=A ( taken caps as there's already 'a' as const. present) , and then plug in A as 0, find t....
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