Question

The distance covered by an oscillating particle in 10s is 1000 cm and the amplitude of it is 1 cm. The frequency of it is​

Answer 1

Answer:

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Answer 2

Given:

Time $=10s$

Distance covered $=1000cm$

Amplitude $=1cm$

To find:

The frequency of the oscillating wave

Solution:

• The amplitude of a wave is called as the maximum displacement of the particle from its mean position or the length of the crest or trough from the mean . Its SI unit is meter (m).

• Wavelength is solely the distance traveled by the wave or the distance between crest or troughs of the adjacent waves. Its SI unit is also meter (m).

• Frequency of a wave is the number of oscillations produced by any oscillating wave in a given specific time period. Its SI unit is per second (s⁻¹).

Solution:

Step 1

We have been given that the particle travels 1000 cm in 10 s and the particle vibrates with an amplitude of 1 cm.

We know that, on completion of a single wave, the distance traveled by the article is $4A$ where, A is the amplitude of the wave.

Therefore, We have

Distance during  $10s=1000cm$

Time for $4 cm$          $T=4cm$  

Therefore,

Time taken by the wave for travelling $4 cm$ or 1 wave will be

$T=\frac{4*10}{1000}$    $;$  $or$

$T=0.04s$

The time taken by particle for travelling the distance of 1 wave is 0.04 s.

Step 2

Now,

According to the definition of frequency,

$f=\frac{1}{T}$

$f=\frac{1}{0.04}$

$f=25Hz$

Final answer:

Hence, the frequency of the wave will be $25rev/s$ or $25 Hz$.