the distance covered by the falling body from rest in the first second and third second are in the ratio of
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the Ratio of distance traveled in first second to that traveled in the 3rd second will be 1:5
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1:5
distance in first second=u+a(t-1/2)=a(1-1/2)=a/2
distance in third second=a(3-1/2)=5a/2
therefore the ratio is 1:5
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