Physics, asked by amitkumarray57, 11 months ago

the distance covered by the falling body from rest in the first second and third second are in the ratio of​

Answers

Answered by QueenOfKnowledge
0

the Ratio of distance traveled in first second to that traveled in the 3rd second will be 1:5

Answered by TisRa
0

1:5

distance in first second=u+a(t-1/2)=a(1-1/2)=a/2

distance in third second=a(3-1/2)=5a/2

therefore the ratio is 1:5

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