the distance from the origin to image of (1,-1) with respect to the line X+y+5 =0
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Answer:
p(123), Plane :x−y+z=5
F is foot of perpendicular form P to plane and I is image,then PF=FI
∴ If (x,y,z)=(r+1,−r+2,r+3) are foot of perpendicular.
⇒(r+1)−(−r+2)+r+3=5⇒r=1
∴F=(2,1,4)
∴I=(3,0,5)
∴ distance of I from origin =
3
2
+0
2
+5
2
=
34
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