the distance from the origin to the point (-12,16) is ?
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Answer:
Step-by-step explanation:
Distance between origin(0,0) and (x, y) = √x² + y²
Here, (x, y) = (-12,-16)
d = √(-12-0)² + (16-0)² = √144+256 = √400
d = 20units.
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The distance from the origin to the point (-12,16) is 20 units
Given:
Point (-12, 16)
To find:
The distance from the origin to the point (-12,16)
Solution:
Let the given point is A (-12, 16) and
As we know the origin is O(0,0)
The formula for the distance between a point P(x, y) from the origin O(0,0) is given by
OP = √(x²+y²)
Then distance between A (-12, 16) and O(0,0)
OA = √(-12)²+16²
= √(144 + 256)
= √400
= √20²
= 20
Therefore, distance OA = 20 units
The distance from the origin to the point (-12,16) is 20 units
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