Question

The distance (in km) of 40 engineers from their residence to their residence to their place of work were found as follows : 5,3,10,20,25,11,13,7,12,31,10,10,12,17,18,11,32,17,16,2,7,8,3,5,12,1518,3,12,14,2,9,6,15,15,7,6,12.constructa grouped frequency distribution table with class size 5 for the data given above taking the first interval as 0-5(5 not including) ​

Answer 1

$\huge\bold\green{Solution:}$

$\sf\color{navy}{The\: data\: is\: represented\: in\: the \:grouped \:frequency\: distribution\: table \:as:}$

$\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\begin{gathered}\boxed{\begin{array}{cccc}\sf Distances\:(in\;k.m ) &\sf Tally\:marks&\sf Frequency \\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad\qquad}{}\\\sf 0-5&\sf ƗƗƗƗ &\sf 5 \\\\\sf 5-10 &\sf ƗƗƗƗ\:ƗƗƗƗ\:I &\sf 11 \\\\\sf 10-15&\sf ƗƗƗƗ\:ƗƗƗƗ\:I&\sf 11 \\\\\sf 15-20&\sf ƗƗƗƗ\:IIII&\sf 9\\\\\sf 20-25&\sf I &\sf 1 \\ \\ \sf 25-30&\sf I&\sf 1 \\ \\ \sf 30-35&\sf II&\sf 2 \\ \\ \\ \sf Total &\sf &\sf 40\\\frac{\qquad \qquad \qquad \qquad}{}&\frac{\qquad \qquad \qquad \qquad}{\bf{}}&\frac{\qquad \qquad \qquad \qquad\qquad}{}\end{array}}\end{gathered}\end{gathered}\end{gathered} \end{gathered}\end{gathered}$