Physics, asked by RAWAT802, 1 year ago

The distance in meters travelled by a particle is related to time by the equation of motion s=7t^2. what is the initial velocity of the particle

Answers

Answered by brunila
0
Velocity is derivative of the distance
So v= ds/dt
Given
s= 7t^2
Then v= d/St(7t^2)
= 14t
If we consider t = 1, then initial velocity is 14
Answered by prakhranjal01
0

Answer: Initial velocity=14 m/ s

Explanation:v=ds/dt

thus, v=d(7t^2)/dt

=7 dt^2/dt

=7*2t

= 14 t

Therefore, considering initial time to be 1 sec.,

Initial velocity=14 m/s.

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