The distance in meters travelled by a particle is related to time by the equation of motion s=7t^2. what is the initial velocity of the particle
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Velocity is derivative of the distance
So v= ds/dt
Given
s= 7t^2
Then v= d/St(7t^2)
= 14t
If we consider t = 1, then initial velocity is 14
So v= ds/dt
Given
s= 7t^2
Then v= d/St(7t^2)
= 14t
If we consider t = 1, then initial velocity is 14
Answered by
0
Answer: Initial velocity=14 m/ s
Explanation:v=ds/dt
thus, v=d(7t^2)/dt
=7 dt^2/dt
=7*2t
= 14 t
Therefore, considering initial time to be 1 sec.,
Initial velocity=14 m/s.
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