Question

The distance is two stations 300 km. Two motorcyclists start simultaneously from these stations and moved towards
each other. The speed of one them is 7 km/hr more than that of the other. If the distance between them after 2 hours of their start is 34 km, find the speed of each motorcyclists.

Answer 1

Answer:

rel speed = x + x+ 7

t

speed =300/2=150

2x=150-7

x= 71.5

x+7=78.5

Answer 2

Answer :D

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EXPLANATION-:

According to the question

After time 2h

300 =(v+ 7) 2 + 34 + v2

[distance = velocity× time]

300 = 2v +14 +34 + 2v

300 = 4v + 48

4v = 252

v = 63 km/h

Check: Put v = 63 in the equation then

RHS converts to

(63 + 7)2 +34+63 x 2

140+ 34+ 126

= 300

Which is equal to L.H.S

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So speed of first motorcyclist is

63km/ph

Second motorcyclist speed is

(63km/ph + 7 ) = 70 km/ph

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First motorcyclist speed = 63km/ph

Second motorcyclist speed = 70 km/ph

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