The distance of 2 planet from the
sun base 10 m 4102 m respectivel
nd the ratio of te
pested & speed of the time
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Answer:
By Kepler's law T^2\propto r^3T
2
∝r
3
or, \dfrac{T_1}{T_2}=\left(\dfrac{r_1}{r_2}\right)^{3/2}
T
2
T
1
=(
r
2
r
1
)
3/2
\dfrac{T_1}{T_2}=\left(\dfrac{10^{13}}{10^{12}}\right)^{3/2}
T
2
T
1
=(
10
12
10
13
)
3/2
\dfrac{T_1}{T_2}=10\sqrt{10}
T
2
T
1
=10
10
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