Math, asked by rajpurohitkalpana85, 5 months ago

the distance of 62.5 kilometre between a and b is represented on the map considered in question 11 what will be the distance in centimetre on the question 11 in a map a distance of 50 km between two places a and b is represented by force at what was the actual distance between a and represented on the map as 7 cm​

Answers

Answered by vedantvborate
0

Step-by-step explanation:

In a map, a distance of 50km between two places A and B is represented by 4cm.

4cm = 50 km

Actual distance between A and D is 62.5km

So, Distance on Map between A and D :

50 km = 4 cm

So,

So, the distance between A and D is 5 cm on the map

Distance between A and C on map = 7 cm

So, Actual distance:

4cm = 50 km

So,  the actual distance between A and C represented on the map as 7cm is 87.5 km

#Learn more :

The scale of a map is 1:5000000.what is the actual distance between two towns, if they are 4cm apart on the map

Answered by amoret520
0

Answer:

Q. 11: 87.5 km

Q. 12: 5 cm

Step-by-step explanation:

Q. 11: Let the actual distance between A and C be x km.

Proportion of the scale of the map to the actual distance.  

4cm/50km = 7cm/xkm  

⇒ 4/5000000 = 7/x                           (converting into cm)

⇒ 1/1250000 = 7/x

⇒ x = 7 × 1250000  

⇒ x = 8750000 cm = 87.5 km  

∴ The actual distance between A and C is 87.5 km.

Q. 12: Let the distance between A to D on the map be y cm.

Proportion of the scale of the map to the actual distance.

4cm/50km = ycm/62.5km

⇒ 4/5000000 = y/6250000                           (converting into cm)  

⇒ 1/1250000 = y/6250000  

⇒ y = 6250000/1250000  

⇒ y = 5cm

∴ The distance between A to D on the map is 5 cm.

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