Question

the distance of a chord of length 16cm from the center of the circle of radius 10cm. is

Answer 1

[tex](radius)^2 = (half of chord)^2 + (distance)^2 [/tex]

$10^2 = [\frac{16}{2} ]^2 + (distance)^2$

$100 = 8^2 + (distance)^2$


100 - 64 = $(distance)^2$

36 = $(Distance)^2$


$\sqrt{36} = distance$

6 cm = distance


i hope this will help you


-by ABHAY