the distance of a point p0,-3from the origin is
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Answered by
2
Answer:
hello....
Distance = √ ( x2-x1)² +( y2-y1)²
given points :- (0,-3) ,(0,0)
distance = √ (0-0)²+(0-(-3))²
= √ 0+9
= √9
= √3²
= 3units......
Hope it helps ...
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Answered by
1
Answer:
since the point p lies in y-axis
hence its distance from origin is -3 units
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