the distance of a reflecting surface from a source is 513m,and speed of source is 342m/s find the time in which the echo return
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Answer:
Speed of sound (v) = 342 ms-1
Echo returns in time (t) = 3 s
Distance travelled by sound = v × t = 342 × 3 = 1026 m
In the given interval of time, sound must travel a distance that is twice the distance of the reflecting surface and source.
Therefore, the distance of the reflecting surface from the source =1026/2 = 513 m.
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Speed of sound (v) = 342 ms-1
Echo returns in time (t) = 3 s
Distance travelled by sound = v × t = 342 × 3 = 1026 m
In the given interval of time, sound must travel a distance that is twice the distance of the reflecting surface and source.
Therefore, the distance of the reflecting surface from the source =1026/2 = 513 m.
Echo return in time (t) =3 s
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