Math, asked by jobanuppal1771, 1 year ago

the distance of a straight line 6x+8y=15 and 3x+4y=9 is

Answers

Answered by 1234567892255
0
6x+8y=15 3x+4y=9
6x+8y-3x-4y=15-9
3x+4y=6
3x+4y-6=180
i think this is the answer but not sure
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