The distance of an integer and in the reciprocal is 143/12.find the integers
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let the integer be x. its reciprocal is 1/x.
ATQ,
x ➕ 1/x=143/12
(x² ➕ 1)/x = 143/12
12x² ➕ 12 =143x
12x²-143x + 12 = 0
12x² -144x -x + 12=0
12x(x - 12) -1(x - 12)=0
(12x - 1)(x - 12)=0
x = 12 or x = 1/12
Hope it helps.
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✔
ATQ,
x ➕ 1/x=143/12
(x² ➕ 1)/x = 143/12
12x² ➕ 12 =143x
12x²-143x + 12 = 0
12x² -144x -x + 12=0
12x(x - 12) -1(x - 12)=0
(12x - 1)(x - 12)=0
x = 12 or x = 1/12
Hope it helps.
✨
✔
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