Question

the distance of B (3,8) from the origin is​

Answer 1

Step-by-step explanation:

the distance of B (3,8) from the origin is 8

Answer 2

Answer:

Given ,

The distance between A(1,2) and B(3,8) is double of the distance of C(3,-1) from the origin

We know that , the distance b/w two points is given by

\boxed{ \sf{D = \sqrt{ {( x_{2} -x_{1} )}^{2} + {(y_{2} -y_{1})}^{2} } }}

D=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

Thus , the distance between A(1,2) and

B(3,8) will be

AB = √{(3 - 1)² + (8 - 2)²}

AB = √{4 + 36}

AB = √40

AB = 2√10 units

Now , the distance between C(3,-1)

from the origin or D(0,0) will be

CD = √{(0 - 3)² + (0 + 1)²}

CD = √{9 + 1}

CD = √10 units

It is observed that ,

CD = 2AB

Hence proved

Step-by-step explanation:

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