The distance of chord AB from the center of a circle is 8cm. length of the chord AB is 12cm. find the diameter of a circle.
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Given length of chord AB = 12 cm.
Distance of chord from center = 8 cm.
OC=8 cm .AC=
2
12
=6 cm
In △OAC
OA
2
=AC
2
+OC
2
OA
2
=(6)
2
+(8)
2
=36+64
[ OA=10 cm].
∴ Diameter of circle is 2(OA) = 20 cm.
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Answered by
0
Answer:
Given length of chord AB = 12 cm.
Distance of chord from center = 8 cm.
OC=8 cm .AC=
2
12
=6 cm
In △OAC
OA
2
=AC
2
+OC
2
OA
2
=(6)
2
+(8)
2
=36+64
[ OA=10 cm].
∴ Diameter of circle is 2(OA) = 20 cm.
solution
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