The distance of chord PQ from the center of circle is 5cm length of the chord PQ is 24cm.then find the radius of circle? math2
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Answer:
26 cm
Step-by-step explanation:
Given AB=24 cm and OC=5 cm
Since, the perpendicular from the centre of the circle to the chord bisects the chord,
AC=CB=12 cm
Join, OA, in △AOC
AO
2
=AC
2
+OC
2
(PythagorasTheorem)
=12
2
+562
=144+25=169
⇒AO=
169
=13cm
∴Diameter=2×=2×AO=2×13cm=26cm
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