Question

The distance of earth and neptuune from the sun are 1.495 ×10^8 km and 44.956 ×10^8 km respectively. Find the orbital period of neptune in years

Answer 1

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# Kepler's Laws of MOTION

- From 3rd law we know that...

T² ~ R³

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Answer 2

distance of the earth from sun ( d1 )=1.496 ×10^8 km

distance of the Neptune from Earth (d2) = 44.956 ×10^8 km

earth complete its revolution around the sun in(t1)= 1 year

W.K.T (from Kepler's third law)

( t2/t1 ) ^2 = (d2/d1)^3

or; t2^2= {(44.956 × 10^8 ÷. 1.496 ×10^8)^3}

or; t2=√27137.39818

ans: t2=164.73 yr