Question

the distance of line 12x+5y=7 from origin

Answer 1

Answer:

hi friends

Step-by-step explanation:

The answer is here,

The length of the perpendicular from the origin to the line 12x+5y+7 =0.

= > \: \frac{ |c| }{ \sqrt{ {a}^{2} + {b}^{2} } }=>a2+b2∣c∣

Here , c = constant.

a= x- coefficient.

b=y- coefficient.

= > \: \frac{ |7| }{ \sqrt{ {5}^{2} + {12}^{2} } }=>52+122∣7∣

= > \: \frac{7}{ \sqrt{ {13}^{2} } }=>1327

= > \: \frac{7}{13}=>137

So, The perpendicular distance from origin to the point 12x+5y+7 =0. is 7/13 units.

:-)Hope it help u.