Question

The distance of origin (0, 0, 0) from the plane -2x+6y-3z=-7 is

Answer 1

Answer:

here is your answer

Step-by-step explanation:

ANSWER

For 3x−6y+2z+5=0 and −4x+12y−3z+3=0 bisector are

9+36+4

​  

 

3x−6y+2z+5

​  

=±  

16+144+9

​  

 

−4x+12y−3z+3

​  

 

The plane which bisects the angle between the plane that contains the origin

13(3x−6y+2z+5)=7(−4x+12y−3z+3)

⇒39x−78y+26z+65+28x−84y+21z−21=0

⇒67x−162y+47z+44=0

Further 3×(−4)+(−6)×12+2×(−3)<0

Hence, the origin lies in the acute angle.