Question

the distance of planet Jupiter from sun is 5.2 times that of earth find the period of jupiter's revolution around the sun

Answer 1

Let
distance of Jupiter Rj and distance of earth Re from Sun
given Rj =5Re
we know
Tsquare provisional R power 3
therefore
(Tj/Te)square=(Rj/Re)qube
(Tj/Te)square=(5Re/Re)qube
Tj =5root 5Te
therefore time of revolution of Jupiter is 5root5 of earth