Question

The distance of point (-1,3) from the line 3x+4y-1=0

Answer 1

SOLUTION

TO DETERMINE

The distance of point (-1,3) from the line

3x + 4y - 1 = 0

EVALUATION

Here the given equation of the line is

3x + 4y - 1 = 0

Hence the required the distance of point (-1,3) from the line 3x + 4y - 1 = 0 is

$\displaystyle \sf{ = \bigg| \frac{(3 \times - 1) + (4 \times 3) - 1}{ \sqrt{ {3}^{2} + {4}^{2} } } \bigg| } \: \: \: unit$

$\displaystyle \sf{ = \bigg| \frac{ - 3 + 12 - 1}{ \sqrt{9 + 16 } } \bigg| } \: \: \: unit$

$\displaystyle \sf{ = \bigg| \frac{8}{ \sqrt{25 } } \bigg| } \: \: \: unit$

$\displaystyle \sf{ = \frac{8}{5} } \: \: \: unit$

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